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** USER: chint **
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** SIMULATION START DATE AND TIME: 28-Apr-2020 10:20:07 **
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** NODE: devnode **
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** OPERATING SYSTEM: WINDOWS 7 **
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** AAAA RRRR IIII AAAA NN NN TTTTTT **
** AAAAAA RRRRR IIII AAAAAA NNN NN TTTTTT **
** AA AA RR RR II AA AA NNNN NN TT **
** AA AA RR RR II AA AA NN N NN TT **
** AAAAAA RRRR II AAAAAA NN NNNN TT **
** AAAAAA RRRR II AAAAAA NN NNN TT **
** AA AA RR RR IIII AA AA NN NN TT **
** AA AA RR RR IIII AA AA NN NN TT **
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** AlgoRIthm for Analysis of Network Thermalhydraulics **
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** VERSION 1.0.0.1.23 **
** Linked on 04-Mar-2020 AT 11:30:00 **
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** DEVELOPED at **
** ============ **
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** AECL (Atomic Energy of Canada Limited) **
** Chalk River Laboratories **
** Thermalhydraulics Branch **
** Chalk River, Ontario **
** CANADA K0J 1J0 **
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** The Software, and all rights with respect thereto shall **
** remain the property of AECL. Users of the Software shall **
** not, directly or indirectly, exploit or disclose to any **
** third party such Software for any purpose without prior **
** written consent of AECL. Users of the Software shall **
** ensure that all persons granted access, shall be similarly **
** bound by these use and disclosure provisions. **
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** ************************************** **
** * ARIANT IS A PROPRIETARY AECL CODE * **
** ************************************** **
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AECL PROTECTED-SENSITIVE
Edwards Blowdown Test
total # nodes 11 total # links 10
############# ARIANT System Control Input Error Summary ###############
No System Control input errors were detected.
System Control Models will be printed at Step = 0 Time = .00000s Dt = .00000 s
Restart record 1 written at simulation step: 0 simulation time: .0000000
Initial conditions loaded from user input file initial conditions at simulation start Time= 0.000000 step= 0
<<< At time: 0.00000 Step #: 1 Dt = Dt(MIN) 0.00000 Iteration Count : 0
Dt(previous): 0.00000 Dt(multiplier): 1.75
0.000 TW: 0.000 RG: 0.000 CV: 0.000 VF: 0.000 VG: 0.000
?other? TWL: Residual Global BRANCH1(R) BRANCH1(R)
?where? (1 1 1 1) in Solution RIGHTBC(L) RIGHTBC(L)
Time= 0.000001 dt= 0.000001 step= 1 Newton iter= 1
<<< At time: 0.00000 Step #: 2 Dt: 0.00000 Iteration Count : 1
Dt(previous): 0.00000 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00001 Step #: 3 Dt: 0.00000 Iteration Count : 1
Dt(previous): 0.00000 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00001 Step #: 4 Dt: 0.00000 Iteration Count : 1
Dt(previous): 0.00000 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00002 Step #: 5 Dt: 0.00001 Iteration Count : 1
Dt(previous): 0.00000 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00003 Step #: 6 Dt: 0.00001 Iteration Count : 1
Dt(previous): 0.00001 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00004 Step #: 7 Dt: 0.00002 Iteration Count : 1
Dt(previous): 0.00001 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00007 Step #: 8 Dt: 0.00003 Iteration Count : 1
Dt(previous): 0.00002 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00011 Step #: 9 Dt: 0.00004 Iteration Count : 1
Dt(previous): 0.00003 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00017 Step #: 10 Dt: 0.00006 Iteration Count : 1
Dt(previous): 0.00004 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
Time= 0.000171 dt= 0.000062 step= 10 Newton iter= 1
<<< At time: 0.00027 Step #: 11 Dt: 0.00010 Iteration Count : 1
Dt(previous): 0.00006 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00042 Step #: 12 Dt: 0.00015 Iteration Count : 1
Dt(previous): 0.00010 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00066 Step #: 13 Dt: 0.00024 Iteration Count : 1
Dt(previous): 0.00015 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00103 Step #: 14 Dt: 0.00037 Iteration Count : 1
Dt(previous): 0.00024 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00161 Step #: 15 Dt: 0.00058 Iteration Count : 1
Dt(previous): 0.00037 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00251 Step #: 16 Dt: 0.00090 Iteration Count : 1
Dt(previous): 0.00058 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00392 Step #: 17 Dt: 0.00141 Iteration Count : 1
Dt(previous): 0.00090 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00613 Step #: 18 Dt: 0.00221 Iteration Count : 1
Dt(previous): 0.00141 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.00958 Step #: 19 Dt: 0.00345 Iteration Count : 1
Dt(previous): 0.00221 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.01498 Step #: 20 Dt: 0.00539 Iteration Count : 1
Dt(previous): 0.00345 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
Time= 0.014977 dt= 0.005393 step= 20 Newton iter= 1
<<< At time: 0.02340 Step #: 21 Dt: 0.00843 Iteration Count : 1
Dt(previous): 0.00539 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.03657 Step #: 22 Dt: 0.01317 Iteration Count : 1
Dt(previous): 0.00843 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.05714 Step #: 23 Dt: 0.02057 Iteration Count : 1
Dt(previous): 0.01317 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.08928 Step #: 24 Dt: 0.03214 Iteration Count : 1
Dt(previous): 0.02057 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
<<< At time: 0.13951 Step #: 25 Dt: 0.05022 Iteration Count : 1
Dt(previous): 0.03214 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
Time= 0.139507 dt= 0.050223 step= 25 Newton iter= 1
<<< At time: 0.21798 Step #: 26 Dt: 0.07847 Iteration Count : 1
Dt(previous): 0.05022 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
Time= 0.217981 dt= 0.078474 step= 26 Newton iter= 1
<<< At time: 0.34060 Step #: 27 Dt: 0.12262 Iteration Count : 1
Dt(previous): 0.07847 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
Time= 0.340596 dt= 0.122615 step= 27 Newton iter= 1
<<< At time: 0.53218 Step #: 28 Dt: 0.19159 Iteration Count : 1
Dt(previous): 0.12262 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
Time= 0.532183 dt= 0.191587 step= 28 Newton iter= 1
<<< At time: 0.83154 Step #: 29 Dt: 0.29935 Iteration Count : 1
Dt(previous): 0.19159 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
Time= 0.831537 dt= 0.299354 step= 29 Newton iter= 1
<<< At time: 1.29928 Step #: 30 Dt: 0.46774 Iteration Count : 1
Dt(previous): 0.29935 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
Time= 1.299279 dt= 0.467742 step= 30 Newton iter= 1
<<< At time: 2.03013 Step #: 31 Dt: 0.73085 Iteration Count : 1
Dt(previous): 0.46774 Dt(multiplier): 1.56
CV: 0.250 0.000 TW: 0.000 RG: 0.000 VF: 0.000 VG: 0.000
Global ?other? TWL: Residual BRANCH1(R) BRANCH1(R)
Solution ?where? (1 1 1 1) in RIGHTBC(L) RIGHTBC(L)
Time= 2.030126 dt= 0.730847 step= 31 Newton iter= 1
Restart record 2 written at simulation step: 31 simulation time: 2.0301258
Total # Newton iterations 31
Elapsed CPU Time Required was 0.14401 s.